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Inclusion of absorption in the model

Everytime a collision takes place the neutron may be absorbed and survives with probability $\gamma(E)={\frac{\Sigma_{s}(E)}{\Sigma_{a}(E)+\Sigma_{s}
(E)}}={\frac{1}{1+{\frac{\Sigma_{a}(E)}{\Sigma_{s}(E)}}}}.$ It follows that the probability distribution after n collisions becomes:

\begin{displaymath}Q(r:n)=P(r:n)\prod_{1}^{n}\gamma\left( E_{i}\right)
\end{displaymath} (4.50)

In the limit when the macroscopic absorption cross-section remains always small as compared to a constant scattering cross-section one obtains:

\begin{displaymath}Q(r:n)=P(r:n)e^{-\ {\sum_{1}^{n}\frac{\Sigma_{a}(E_{i})}{\Sigma_{s}(E)}}}
\end{displaymath} (4.51)

Since the average energy interval is $\xi E_{i}$ the sommation may be approximated by an integral:

\begin{displaymath}\sum_{1}^{n}\Sigma_{a}(E_{i})=\int_{E_{0}}^{E_{n}}{\frac{\Sigma_{a}(E)}{\xi
E\Sigma_{s}(E)}}dE
\end{displaymath} (4.52)

Thus we can obtain the age distribution, including small absorption:


 \begin{displaymath}q(r,\tau)=\frac{e^{-\frac{r^{2}}{4\tau}}e^{-\int_{E_{0}}^{E(\...
...a}(E)}{\xi E\Sigma_{s}(E)}}dE}}{\left( 4\pi\tau\right)
^{3/2}}
\end{displaymath} (4.53)

A very similar expression is obtained for an hydrogen scatterer.